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9x^2+21x-144=0
a = 9; b = 21; c = -144;
Δ = b2-4ac
Δ = 212-4·9·(-144)
Δ = 5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5625}=75$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-75}{2*9}=\frac{-96}{18} =-5+1/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+75}{2*9}=\frac{54}{18} =3 $
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